Source Code for Module concurrent_tree_crawler.common.resources

 1  import os.path 
 2  from pkg_resources import resource_stream 
 3   
 4 -class Resources: 
 5          @staticmethod 
 6 -        def open(_name_, relative_file_path): 
 7                  """Safe way of accessing the resource file (it will work even in 
 8                          code enclosed in *.egg/*.zip package) 
 9                   
10                          @param _name_: C{__name__} variable (of the calling module) 
11                          @return: file-like object""" 
12                   
13                  return resource_stream(_name_, relative_file_path) 
14           
15          @staticmethod 
16 -        def path(_file_, relative_path): 
17                  """*Unsafe* way of getting path to a resource (dir/file) - it won't  
18                          work inside code enclosed in *.egg/*.zip package 
19                           
20                          @param _file_: C{__file__} variable of calling module 
21                          @return: absolute-like path to given resource""" 
22                   
23                  return os.path.join(os.path.dirname(_file_), relative_path) 
24